lim_(x rarr(pi)/(4))(1-tan theta)/(1=sqrt(2)sin theta)

lim_(theta rarr(pi)/(4))(1-tan theta)/(1-sqrt(2)sin theta)

Putting z=x-(pi)/(4), show that lim_(x rarr(pi)/(4))(1-tan x)/(1-sqrt(2)sin x)=2

lim_(x rarr(pi)/(2))(1-sin theta)/(((pi)/(2)-theta)cos theta)=

the value of lim_(x rarr(pi)/(2))(sec theta-tan theta)

Find lim {x rarr (pi) / (4)} (1-tan x) / (1-sqrt (2) sin x)

lim_(x rarr((pi)/(2)))(1-sin x)tan x=

Evaluate : underset ( theta rarr pi //4) ( "lim") ((1- tan theta))/( (1- sqrt(2) sin theta ))

lim_(t rarr((pi)/(2)))int_(0)^(1)tan theta sqrt(cos theta)ln(cos theta)d theta is equal

If f(x) is continuous at theta= pi/4 , where f(theta)={:{((1-tan theta)/(1-sqrt(2)sin theta) ", for " theta!=pi/4),(k/2 ", for " theta=pi/4):} , then k=

The value of lim_(theta rarr0^(+))(sin sqrt(theta))/(sqrt(sin theta)) is equal to