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[" Given that "a alpha^(2)+2b alpha+c!=0...

[" Given that "a alpha^(2)+2b alpha+c!=0" and that the system of equations "],[(a alpha+b)x+ay+bz=0,(b alpha+c)x+by+cz=0],[(a alpha+b)y+(b alpha+c)z=0" has a non trivial solution,then "a,b,c" are in "]

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