[" Let PS be the median of the triangle with vertices "P(2,2),Q(6,-1)" and "R(7,3)" .The "],[" equation of the line passing through "(1,-1)" and parallel to "PS" is "]

Let PS be the median of the triangle with vertices P (2 ,2) , Q (6 , -1) and R (7 , 3) . The equationf o the line passing through (1 , -1) and parallel to Ps is _

Let P S be the median of the triangle with vertices P(2,2),Q(6,-1)a n dR(7,3) Then equation of the line passing through (1,-1) and parallel to P S is

Let PS be the median of the triangle with vertices P(2,""2),""Q(6,-1)""a n d""R(7,""3) . The equation of the line passing through (1,-1) and parallel to PS is (1) 4x-7y-11""=""0 (2) 2x+""9y+""7""=""0 (3) 4x+""7y+""3""=""0 (4) 2x-9y-11""=""0

Let PS be the median of the triangle with vertices P(2,""2),""Q(6,-1)""a n d""R(7,""3) . The equation of the line passing through (1,-1) and parallel to PS is (1) 4x-7y-11""=""0 (2) 2x+""9y+""7""=""0 (3) 4x+""7y+""3""=""0 (4) 2x-9y-11""=""0

(1)the points (1,3) and (5,1) are two opposite vertices of rectangle. the other two vertices lie on the line y=2x+c, the remaining vertices are ? (2) Let PSbe the median of the triangle with vertices P(2,2),Q(6,-1),R(2,3).the equation of the line passing through (1,-1)and parallel to PSis

Let PS be the median of the triangle with vertices P(2,2),Q(6,-1) and R(7,3) Then equation of the line passing through (1,-1) and parallel to PS is 2x-9y-7=02x-9y-11=02x+9y-11=02x+9y+7=0

Let P S be the median of the triangle with vertices P(2,2),Q(6,-1)a n dR(7,3) Then equation of the line passing through (1,-1) and parallel to P S is 2x-9y-7=0 2x-9y-11=0 2x+9y-11=0 2x+9y+7=0

Let P S be the median of the triangle with vertices P(2,2),Q(6,-1)a n dR(7,3) Then equation of the line passing through (1,-1) and parallel to P S is 2x-9y-7=0 2x-9y-11=0 2x+9y-11=0 2x+9y+7=0