If reation between distance and time is `s =a + bt + ct ^(2)` find initial velocity and acceleratin

If reation between distance and time is s =a + bt + ct ^(2) find initial velocity and acceleration.

The displacement of a particle is given by y = a + bt + ct^2 - dt^4 . The initial velocity and acceleration are respectively.

The displacement of a particle is given by y = a + bt + ct^2 - dt^4 . The initial velocity and acceleration are respectively.

The displacement of a particle is given by y = a + bt + ct^2 - dt^4 . The initial velocity and acceleration are respectively.

The displacement of a particle is given by y = a +bt+ct^(2)+dt^(4) . The initial velocity and acceleration are respectively

For a moving particle the relation between the distance (S) and time (t) is S = a+bt + ct^(2)+dt^(3) , which one among a,b,c and d will represent the dimension of acceleration ?

Displacement of a particle moving in a straight line is represented as follows: x=at^(3)+bt^(2)+ct+d Ratio of initial velocity to initial acceleration depends.

Draw a velocity-time graph for a body moving with an initial velocity u and uniform acceleration a. Use this graph to find the distance travelled by the body in time t.