`tan^(- 1)((dy)/(dx))=x+y`

(x (dy) / (dx) -y) tan ^ (- 1) ((y) / (x)) = x

3. (1+x^(2))tan^(-1)x(dy)/(dx)+y=0

Solve the differential equation: (i) (1+y^(2))+(x-e^( tan ^(-1)y))(dy)/(dx)=0 (ii) x(dy)/(dx)+cos^(2)y=tan y(dy)/(dx)

if y=sec(tan^(-1)x)then(dy)/(dx) is

Express (x-y "tan"^(-1)(y)/(x))dx+x "tan"^(-1) (y)/(x)dy=0 in the form F((y)/(x))=(dy)/(dx) .

If y=tan^(-1)x ,then (dy)/(dx) is

If y=tan^(-1)((1+x)/(1-x)) then (dy)/(dx)=

If y=tan^(-1) ((1+x)/(1-x)) then (dy)/(dx)=

If y=tan^(-1)((1-x)/(1+x)), find (dy)/(dx)

If y=tan^(-1)((1-x)/(1+x)) , find (dy)/(dx) .