For `M^(2+)+2e^(-)rarrM:0.275` g of metal M is depoited at cathode on passing 1 A of current for 965 s. the atomic mass of metal M is

M^(2+) +2e rarr M. 0.275 g of metal M is deposited at the cathode due to passage of 1A of current for 965s. Hence atomic weight of the metal M is:-

M^(2+) +2e rarr M. 0.275 g of metal M is deposited at the cathode due to passage of 1A of current for 965s. Hence atomic weight of the metal M is:-

M^(2+) +2e rarr M. 0.275 g of metal M is deposited at the cathode due to passage of 1A of current for 965s. Hence atomic weight of the metal M is:-

A metal nitride M_(3)N_(2) contains 28 % of nitrogen. The atomic mass of metal M is

A metal nitride M_(3)N_(2) contains 28 % of nitrogen. The atomic mass of metal M is

13g of metal M is deposited at cathode by passing 0.4F of electricity . The cathodic reaction is : M^(n+)+n e^(-) rarr M The formula of metal chloride (Aw=65) is …………………….. .

13g of metal M is deposited at cathode by passing 0.4F of electricity . The cathodic reaction is : M^(n+)+n e^(-) rarr M The formula of metal chloride (Aw=65) is …………………….. .

0.59g of a metal is deposited at the cathode when 0.5A current is passed for 1 hr through a soluiton of metal sulphate. Find the equivalent mass or chemical equivalent of the metal.

A metal M of atomic mass A forms an oxide of the formula M_(x)O_(y) . The equivalent mass of metal is given by

A metal 'M' is known to form the fluoride MF_(2) . When 10 A of electricity is passed through the molten salt for 330 s, 1.950 g of metal is deposited . The atomic mass of M is _________.