A speeder moves at a constant `15m//s` in a school zone A police car starts from rest just as the speeder passed it.The police car accelerates at.`2 m//s^(2)` until it reaches its.maximum velocity of `20 m//s.`Where and when does the speeder get caught ?

A car is speeding at 25 m//s in a low speed zone .A police car starts from rest just as the speeder passes and accelerates at a constant rate of 5m//s^(2) (a) When does the police car catch the speeding car? (b) How fast in the police car travelling when it catches up with the speeder ? How for have the cars travelled when the police car catches the speeder?

A car starts from rest and covers 25m in 5s. Calculäte the acceleration of the car.

A car accelerates uniformly at 4 m s^(-2) from rest. Find its velocity at the end of 5 seconds.

A car starting from rest acquires a velocity 180 m s^(-1) in 0.05 h. Find the acceleration.

A car starts from rest and moves with a uniform acceleration of 2 m//s^(2) . What will be its velocity after it covers a distance of 49 m? How much time will it take to cover the distance of 49 m?

A car starts from rest and moves with uniform acceleration of 5 m//s^(2) for 8 sec. If the acceleration ceases after 8 seconds then find the distance covered in 12s starting from rest.