Home
Class 11
PHYSICS
A stone is projected with speed of 50 ms...

A stone is projected with speed of `50 ms^(-1)` at an angle of `60^(@)` with the horizontal. The speed of the stone at highest point of trajectory is

Promotional Banner

Similar Questions

Explore conceptually related problems

A shell is fired from a cannot with a speed of 100ms^(-1) at an anlge 60^(@) with the horizontal (x-direction). At the highest point of its trajectory the shell explodes into two equal fragments. One of the fragments moves along the negative x-direction with a speed of 50 ms^(-1). What is the speed of the other fragment at the time of explosion ?

A boy throws a stone with a speed of V_(0) = 10 m/sec at an angle of theta_(0)= 30^(@) to the horizontal Find the position of the stone wrt the point of projection just after a time t = 1/2 sec.

A boy throws a stone with a speed of V_(0) = 10 m/sec at an angle of theta_(0)= 30^(@) to the horizontal Find the position of the stone wrt the point of projection just after a time t = 1/2 sec.

A particle is projected with speed u at angle theta to the horizontal. Find the radius of curvature at highest point of its trajectory

A particle is projected with speed u at angle theta to the horizontal. Find the radius of curvature at highest point of its trajectory

A stone is thrown vertically at a speed of 30 ms^(-1) making an angle of 45^(@) with the horizontal. What is the maximum height reached by the stone ? Take g=10 ms^(-2) .

A stone is thrown vertically at a speed of 30 ms^(-1) taking an angle of 45^(@) with the horizontal. What is the maximum height reached by the stone ? Take g = 10 ms^(-2) .

A particle is projected with speed 'u' at an angle 60^@ with horizontal, then find the speed when its angle with horizontal changes to 30^@ .

A particle is projected from the ground with an initial speed of u at an angle of projection theta . The average velocity of the particle reaches highest point of trajectory is

A stone is thrown with a speed of 10 ms^(-1) at an angle of projection 60^(@) . Find its height above the point of projection when it is at a horizontal distance of 3m from the thrower ? (Take g = 10 ms^(-2) )