Two capacitors `2muF` and `4muF` are connected in parallel. A third capacitor of `6muF`is connected in series. The combination is then connected across a `12V` battery. The voltage across `2muF` capacitor is:

Two capacitrors of 2 muF and 4 muF are connected in parallel. A third capacitor of 6 muF is connected in series. The combaination is connected across a 12 V battery. The voltage across 2 mu F capacitor is

Two capacitrors of 2 muF and 4 muF are connected in parallel. A third capacitor of 6 muF is connected in series. The combaination is connected across a 12 V battery. The voltage across 2 mu F capacitor is

Two capacitors 2 muF and 4 muF are connected in parallel. A third capacitor of 6 muF capacity is connected in series. The combination is connected across a 12 V battery. The voltage across a 2 muF capacitor is

Two capacitor each of capacity 4muF are connected in series and third capacitor of capacity 4muF is connected in parallel with the combination. The equivalent capacitance of the arrangement is

Three capacitors of capacitances 2muF,3muF and 4muF are connected in sereis. What is the total capacitance of the combination?

Two capacitors have a capacitance of 5 muF when connected in parallel and 1.2 muF when connected in series. Calculate their capacitance.

Two capacitors 3muF and 6muF are connected in series across a potential difference of 120V . Then the potential difference across 3muF capacitor is: