A ring mass `m` and radius `R` has three particle attached to the ring as shown in the figure. The centre of the centre `v_(0)`. Find the kinetic energy of the system. (Slipping is absent).
.

A ring of mass m and radius R has four particles each of mass m attached to the ring as shown in figure. The centre of ring has a speed v_(0). The kinetic energy of the system is

A uniform ring of mass m and radius R is in uniform pure rolling motion on a horizontal surface. The velocity of the centre of ring is V_(0) . The kinetic energy of the segment ABC is:

Three rings each of mass M and radius R are arranged as shown in the figure. The moment of inertia of the system about YY¢ will be

Four rings each of mass M and radius R are arranged as shown in the figure. The moment of inertia of the system about YY' will be

Four rings each of mass M and radius R are arranged as shown in the figure. The moment of inertia of the system about YY' will be

A uniform ring of mass m and radius R is performing pure rolling motion on a horizontal surface. The velocity of centre of the ring is V_(0) . If at the given instant the kinetic energy of the semi circular are AOB is lambda mv_(0)_(2) , then find the value of 11lambda ("take" pi=(22)/(7))

A uniform ring of mass m and radius R is performing pure rolling motion on a horizontal surface. The velocity of centre of the ring is V_(0) . If at the given instant the kinetic energy of the semi circular are AOB is lambda mv_(0)_(2) , then find the value of 11lambda ("take" pi=(22)/(7))

A uniform ring of mass m and radius R is performing pure rolling motion on a horizontal surface. The velocity of centre of the ring is V_(0) . If at the given instant the kinetic energy of the semi circular are AOB is lambda mv_(0)_(2) , then find the value of 11lambda ("take" pi=(22)/(7))