Redefine the function `f(x)=|x-2|+|2+x|,-3lt=xlt=3`

Redefine the function f(x)= |x-2| + |2 + x|, -3 le x le 3

Redefine the function f(x)= |1+x| +|1-x|, -2 le x le 2 .

The range of the function f(x)=|x-1|+|x-2|,-1lt=xlt=3, is [1,3] (b) [1,5] (c) [3,5] (d) none of these

The range of the function f(x)=|x-1|+|x-2|,-1lt=xlt=3, is [1,3] (b) [1,5] (c) [3,5] (d) none of these

Verify Rolles theorem for the function f(x)=x(x-3)^2,\ 0lt=xlt=3 .

Discuss the applicability of Rolles theorem on the function f(x)={(x^2+1 ,, if \ 0lt=xlt=1),(3-x ,,if 1ltxlt=2):}

Examine the continuity of the function f(x)={3x-2,\ \ \ xlt=0x+1,\ \ \ x >0 at x=0 . Also sketch the graph of this function.

Consider the function f(x)={2x+3,xlt=1-x^2+6,x >1

Consider the function f(x)={2x+3,xlt=1-x^2+6,x >1

The points of discontinuity of the function f(x)={2sqrt(x)\ \ \ ,\ \ \ 0lt=xlt=1 ,\ \ \4-2x\ \ \ ,\ \ \ 1< x