When a projectile is fired at an angle `theta` w.r.t horizontal with velocity u, then its vertical component:

A projectile is fired at an angle theta with the horizontal with velocity u. Deduce the expression for the maximum height reached by it.

If a projectile is fired at an angle theta with the vertical with velocity u, then maximum height attained is given by:-

If a projectile is fired at an angle theta with the vertical with velocity u, then maximum height attained is given by:-

If a projectile is fired at an angle theta with the vertical with velocity u, then maximum height attained is given by:-

A projectile is fired at an angle of 30^(@) with the horizontal such that the vertical component of its initial velocity is 80m/s. Find approximatly the velocity of the projectile at time T//4 where T is time of flight.

In projectile motion, a body is projected at an angle theta with velocity u then the horizontal component of velocity will be

A projectile is fired at an angle of 30^(@) to the horizontal such that the vertical component of its initial velocity is 80m//s . Its time of fight is T . Its velocity at t=T//4 has a magnitude of nearly.