If `A, B, C, D` be the angles of acyclic quadrilateral, show that : `cosA +cosB+cosC+cosD=0`.

If A,B,C,D are the angles of a cyclic quadrilateral, show that cosA+cosB+cosC+cosD=0

If A,B,C and D are the angles of cyclic quadrilateral, prove that: i) cosA + cosB+cosC+cosD = 0 ii) cos(180^(@)-A)+cos(180^(@)+B)+cos(180^(@)+C)-sin(90^(@)+D) = 0

If A , B , C ,D are angles of a cyclic quadrilateral , then prove that cosA + cosB+cosC+cosD=0.

If A,B,C and D are the angles of cyclic quadrilateral, prove that: i) cosA + cosB+cosC+cosD ii) cos(180^(@)-A)+cos(180^(@)+B)+cos(180^(@)+C)-sin(90^(@))

If A,B,C,D are angles of a cyclic quadrilateral, then the value of cosA+cosB+cosC+cosD is

In a cyclic quadrilateral ABCD, then find cosA+cosB+cosC+cosD=?

In any quadrilateral ABCD, show that: cosA cosB-cosC cosD="sin"A "sin"B-"sin"C "sin"D.

If ABCD is a cyclic quadrilateral, then the value of cosA-cosB+cosC-cosD is equal to

If ABCD is a cyclic quadrilateral, then the value of cosA-cosB+cosC-cosD is equal to

Let A,B,C,D be the angles of a quadrilateral . If they are concyc lic , then the value of cosA+cosB+cosC+cosD is