If dissociation for reaction, `PC1_(5)hArrPC1_(3) + C1_(2)` is `20%` at 1 atm pressure. Calculate `K_(c)`.

Phosphorus pentachloride dissociates as follows, ina closed reaction vessel, PC1_(5(g))hArrPC1_(3(g)) + C1_(2(g)) If total pressure at equilibrium of the reaction mixture is P and degree of dissociation of PC1_(5) is x, the partial pressure of PC1_(3) will be:

Phosphorus pentachloride dissociates as follows, ina closed reaction vessel, PC1_(5(g))hArrPC1_(3(g)) + C1_(2(g)) If total pressure at equilibrium of the reaction mixture is P and degree of dissociation of PC1_(5) is x, the partial pressure of PC1_(3) will be:

K_p for the reaction : N_2O_4(g) hArr 2NO_2(g) is 0.157 atm at 27^@C and 1 atm pressure . Calculate K_c for the reaction.

Assertion: Association of an inert gas at constant pressure to dissociation equilibrium of PC1_(5) hArr PC1_(3) + C1_(2) favours forward reaction. Reason: K_(c) =(alpha^(2))/(V(1 - alpha)) for the dissociation equilibrium of PC1_(5) where alpha is degree of dissociation of PC1_(5) .

In the following reaction PC1_(5)(g)hArrPC1_(3)(g) + C1_(2)(g) at constant temperature, rate of backward reaction is increase by:

The reaction, PC1_(5)hArrPC1_(3) + C1_(2) is started in a 5 litre container by taking one mole of PC1_(5) . If 0.3 mole of PC1_(5) is there at equilibrium, concentration of PC1_(3) and K_(c) will respectively be:

The degree of dissociation of PC1_(5) (alpha) obeying the equilibrium, PC1_(5)hArrPC1_(3) + C1_(2) , is approximately related to the pressure at equilibrium by (given alpha ltlt 1 ) :