दी गई आकृति में, `triangle ABC` तथा `triangle AMP` क्रमशः Bतथा M पर समकोण है तो सिद्ध कीजिए कि,
(i) `triangle ABC ~ triangle AMP`
(ii) `(CA)/(PA) = (BC)/(MP)`

In Fig., ABC and AMP are two right triangles, right angled at B and M respectively. Prove that: (i) triangleABC ~ triangleAMP (ii) (CA)/(PA) = (BC)/(MP)

In a triangle ABC if angle ABC=60^(@) , then ((AB-BC+CA)/(r ))^(2)=

In a triangle ABC if angle ABC=60^(@) , then ((AB-BC+CA)/(r ))^(2)=

In a triangle ABC if angle ABC=60^(@) , then ((AB-BC+CA)/(r ))^(2)=

triangle ABC ~ traingle AMP are two right triangles right angled at B and M respectively. Prove that triangle ABC ~ triangle AMP

Let triangle ABC and triangle ABD be on the same base AB and between the same parallels AB and CD. Then the relation between areas of triangle ABC and triangle ABD will be: मान लीजिये कि triangle ABC तथा triangle ABD एक ही आधार AB पर स्थित हैं तथा समान समानांतर रेखाओं AB तथा CD के बीच हैं| triangle ABC तथा triangle ABD के क्षेत्रफलों में क्या संबंध होगा ?

Delta ABC and Delta AMP are two right triangles right angled at B and M respectively. Prove that (i) Delta ABC ~ Delta AMP and (ii) (CA)/(PA) = (BC)/(MP) .

triangle ABC ~ triangle RQP and AB = 4 cm , BC = 6 cm and AC = 5 cm. If ar(triangle ABC) : ar (triangle PQR)=9:4 , then PQ is equals to : triangle ABC ~ triangle RQP है तथा AB = 4 सेमी, BC = 6 सेमी और AC = 5 सेमी है | यदि ar(triangle ABC) : ar (triangle PQR)=9:4 ,है, तो PQ किसके बराबर है ?

The perimeter of triangle ABC and triangle DEF are 43.2 cm and 28.8 cm, respectively, and triangle ABC ~ triangle DEF . If DE =12cm, then the length of AB is: triangle ABC और triangle DEF की परिधि क्रमशः 43.2 सेमी और 28.8 सेमी है, और triangle ABC ~ triangle DEF | यदि DE =12 सेमी है, तो AB की लंबाई है

In the given figure, Delta ABC and Delta AMP are right- angled at B and M respectively. Prove that (i) Delta ABC ~~Delta AMP (ii) (CA)/(PA)=(BC)/(MP)