As an air bubble rises from the bottom of a lake to the surface, its volume is doubled. Find the depth of the lake. Take atmospheric pressure = 76 cm of Hg.

when an air bubble rises from the bottom to the surface of a lake, its radius becomes double . Find the depth of the lake , given that the atmospheric pressure is equal to the pressure due to a column of water 10 m high. Assume constant temperature and disreged surface tension .

When an air bubble rises from the bottom of a lake to the surface, its radius, is doubled. Atmospheric pressure is equal' to the pressure of a water column of height it. Depth of the lake is-

When an air bubble rises from the bottom of a lake to the surface,its radius is doubled. Atmospheric pressure is equal to the pressure of a water column of height H. Depth of the lake is

When an air bubble rises from the bottom of a lake to the upper surface , its diameter increases from 1mm to 2mm. IF the atmospheric pressure is 76 cmHg,calculate the depth of the lake. Density of mercury is 13.6g.cm^-3 .

A bubble rises from the bottom of a lake 90m deep on reaching the surface, its volume becomes (take atmospheric pressure equals to 10 m of water)

When a large bubble rises from the bottom of a lake to the surface, its radius doubles. The atmospheric pressure is equal to that of a column of water of height H. The depth of the lake is

When a large bubble rises from the bottom of a lake to the surface , its radius doubles .The atmospheric pressure is equal to that of a column of water of height H. What is the depth of the lake ?

When a large bubble rises from the bottom of a lake to the surface, its radius doubles, The atmospheric pressure is equal to that of a column of water of height H. The depth of the lake is

When a large bubble rises from the bottom of a lake to the surface its radius doubles. If atmospheric pressure is equal to that of column of water height H then the depth of lake is