" (iv) "(sin3 theta)/(sin theta)-(cos3 theta)/(cos theta)=2

(sin 3theta)/(sin theta)-(cos 3theta)/(cos theta)=

Prove that, (sin 3 theta)/(sin theta)-(cos 3 theta)/(cos theta)=2

Prove that (sin 3 theta)/( sin theta) - (cos 3 theta)/(cos theta) = 2

The value of the expression ((sin3 theta)/(sin theta))^(2)-((cos3 theta)/(cos theta))^(2) when theta=7.5^(@)

((sin3 theta)/(sin theta))^(2)-((cos3 theta)/(cos theta))^(2)=a cos2 theta wherever it id defined.Then the value of a is

(sin 3 theta)/(sin theta)-(cos 3 theta)/(cos theta)= A) sin 2 theta B) cos 4 theta C)1D)2

( sin 3 theta )/( sin theta ) -(cos 3 theta )/( cos theta )=

Solve (3 sin theta-sin 3 theta)/(sin theta)+(cos 3 theta)/(cos theta)=1 .

Solve (3 sin theta-sin 3 theta)/(sin theta)+(cos 3 theta)/(cos theta)=1 .

Solve (3 sin theta-sin 3 theta)/(sin theta)+(cos 3 theta)/(cos theta)=1 .