10 gram of solute with molecular mass 100 gram `mol^(-1)` is dissolved in 100 gram solvent to show `0.3^(@)C` elevation in boiling point. The value of molal ebuilioscopic constant will be:

10 g of solute with molecular mass 100 g mol^(-1) dissolved in 100 g of solvent to show 0. 3^@ elevation in boiling point. The value of molal ebullioscopic constant will be

If 1 g of solute (molar mass = 50 g mol^(-1) ) is dissolved in 50 g of solvent and the elevation in boiling point is 1 K. The molar boiling constant of the solvent is

If 1 g of solute (molar mass = 50 g mol^(-1) ) is dissolved in 50 g of solvent and the elevation in boiling point is 1 K. The molar boiling constant of the solvent is

10 grams of a solute is dissolved in 90 grams of a solvent. Its mass percent in solution is

Calculate the molecular mass of a substance 1.0 g of which on being dissolved in 100 g of solvent gave an elevation of 0.307 K in the boiling point. (Molal elevation constant (k_b)=1.84 K//m .

0.1 gram mole of urea dissolved in 100 g of water. The molality of the solution is