Find the equation of the plane through the line of intersection of the planes `x+2y+3z+2=0`, `2x+3y-z+3=0` and perpendicular to the plane `x+y+z=0`

Find the equation of the plane passing through the line of intersection of the planes 2x-y=0 and 3z-y=0 , and perpendicular to the plane 4x+5y-3z=9 .

Find the equation of the plane through the line of intersection of the planes x+y+z=1 and 2x+3y+4z=5 which is perpendicular to the plane x-y+z=0

The equation of plane through the line of intersection of the planes 2x+3y+4z-7=0,x+y+z-1=0 and perpendicular to the plane x+y+z-1=0

Find the equation of the plane passing through the line intersection of the plane: 2x-y=0 and 3z-y=0 and perpendicular to the plane 4x+5y-3z=8

The equation of the plane passing through the line of intersection of the planes x + y + 2z = 1,2x + 3y + 4z = 7, and perpendicular to the plane x - 5y + 3z = 5 is given by:

Find the equation of the plane through the line of intersection of the planes x+y+z=1 and 2x+3y+4z=5 which is perpendicular to the plane x-y+z=0 Then find the distance of plane thus obtained from the point A(1,3,6) .

Find the equation of the plane through the line of intersection of the planes x+y+z=1 and 2x+3y+4z=5 , which is perpendicular to the plane x-y+z=0 . Also find the distance of the plane so obtained from the origin.

Find the equation of the plane passing through the intersection of the planes 2x+3y-z+1=0 and x+y-2z+3=0 and perpendicular to the plane 3x-y-2z-4=0

Find the equation of the plane through the line of intersection of the planes x+y+z=1 and which is perpendicular to the plane x-y+z=0

Find the equation of the plane passing through the intersection of the planes 2x-3y+z-4=0 and x-y+z+1=0 and perpendicular to the plane x+2y-3z+6=0