The equation of the normal to the curve `2y+x^(2)=3` at the point `(1,1)` is

The equation of the normal to the curve y=x(2-x) at the point (2, 0) is

Equation of the normal to the curve y=-sqrt(x)+2 at the point (1,1)

If 3x+4y-k is the equation of the normal to the curve x^(2)+2x-3y+3=0 at the point (1,2) ,then the value of k=

Equation of normal to the curve y^(2)=(x)/(2-x) at the point (1,1) is

Find the equation of the normal to curve y^(2)=4x at the point (1, 2) .

The equation of normal to the curve y= x ^(2) + 2 at point (1,1) is :

The equation of normal to the curve x^(2)=3-2y at (1,1) is :

The equation of the normal to the curve y= e^(-2|x|) at the point where the curve cuts the line x=-(1)/(2), is

Find the equation of the normal to the curve a y^2=x^3 at the point (a m^2,\ a m^3) .

The equation of the normal to the curve y=e^(-2|x|) at the point where the curve cuts the line x = 1//2 is