A proton of velocity `(3hati+2hatj) ms^(-1)` enters a field of magnetic induction in the proton in (specific charge of proton `=0.96xx10^(8) Ckg^(-1)`) `[F=q(vec(v)xxvec(B))]`

A proton of velocity (3hati+2hatj)ms^(-1) enters a field of magnetic induction (2hatj+3hatk) T , the acceleration produced in the proton in ms^(-2) is (specific charge of proton = 0.96xx10^(8)C-kg^(-1) )

A proton is projected with a velocity of 3X10^6 m s ^(-1) perpendicular to a uniform magnetic field of 0.6 T. find the acceleration of the proton.

A proton is projected with a velocity of 3X10^6 m s ^(-1) perpendicular to a uniform magnetic field of 0.6 T. find the acceleration of the proton.

A proton is projected with a velocity of 3X10^6 m s ^(-1) perpendicular to a uniform magnetic field of 0.6 T. find the acceleration of the proton.

A proton beam enters a magnetic field of 10^(-4) " Wb " m^(-2) Wb normally. If the specific charge of the proton is 10^(11) " C " kg^(-1) and its velocity is 10^(9) " m "s^(-1) then the radius of the circle described will be

A proton is projected with a velocity 10^(7)ms^(-1) , at right angles to a uniform magnetic field of induction 100mT . The time ( in second ) taken by the proton to traverse 90^(@) are is : ( Mass of proton =1.65xx10^(-27)kg an charge of proton =1.6 xx10^(-19)C)