Cosine of an angle between the vectors `(vec a+vec b)` and `(vec a- vec b)` If `|vec a|=2,|vec b|=1` and `vec a ^^ vec b=60^@` is

cosine of an angle between the vectors (vec a+vec b) and (vec a-vec b) if |vec a|=2,|vec b|=1 and angle between vec a and vec b=60^(^^)2^(@) is

Find the angle between two vectors vec a and vec b, if |vec a xxvec b|=vec a*vec b

If theta is the angle between the vectors vec a and vec b then (|vec a xx vec b|)/(|vec a . vec b|) =

Find the angle between two vectors vec a and vec b , if | vec a xx vec b|= vec a . vec b .

If vec a and vec b are non - zero vectors and |vec a+ vec b| = |vec a - vec b| , then the angle between vec a and vec b is

If vec a and vec b are unit vectors such that ( vec a+ vec b).[(2 vec a+3 vec b)xx(3 vec a-2 vec b)]=0 , then angle between veca and vec b is

If vec a and vec b are unit vectors such that |vec a xx vec b| = vec a . vec b , then |vec a + vec b|^(2) =

If vec a and vec b are vectors such that |vec a + vec b| = |vec a - vec b| , then the angle between vec a and vec b is

If vec a and vec b are unit vectors find the angle between vec a+vec b and vec a-vec b

The lengths of the diagonals of a parallelogram constructed on the vectors vec p=2vec a+vec b and vec q=vec a-2vec b where vec a&vec b are unit vectors forming an angle of 60^(@) are: