Dimensions of an unknown quantity ,`phi = (ma)/(alpha) log (1 +(alpha l)/(ma))` where `m =` mass, `a=` acceleration and `l = "length"` are

An unknown quantity ''alpha'' is expressed as alpha = (2ma)/(beta) log(1+(2betal)/(ma)) where m = mass, a = acceleration l = length, The unit of alpha should be

An unknown quantity ''alpha'' is expressed as alpha = (2ma)/(beta) log(1+(2betal)/(ma)) where m = mass, a = acceleration l = length, The unit of alpha should be

Dimension of a physical quantity is M^(a)L^(b)T^(c) , then it is ......

In a book, the answer for a particular question is expressed as b=(ma)/(k)[sqrt(1+(2kl)/(ma))] here m represents mass, a represent acceleration, l represent length. The unit of b should be :-

In a book, the answer for a particular question is expressed as b=(ma)/(k)[sqrt(1+(2kl)/(ma))] here m represents mass, a represent acceleration, l represent length. The unit of b should be :-

In a book, the answer for a particular question is expressed as b=(ma)/(k)[sqrt(1+(2kl)/(ma))] here m represents mass, a represent acceleration, l represent length. The unit of b should be :-

In a book, the answer for a particular question is expressed as. b=(ma)/(l)[sqrt(1+(2kl)/(ma)] . Here m represents mass, 'a' represents acceleration, l represents length. The unit of 'b' should be in SI system)

The dimension of the physical quantity alpha in the equation. E = V alpha . Where E is the energy and V is voulume has same dimesion as of