" 22."quad (sec8A-1)/(sec4A-1)" is equal to "

(sec 8 A-1)/( sec 4A-1)=

sec(cosec^-1x) is equal to

(sec8A-1)/(sec4A-1) is equal to (A) (tan2A)/(tan8A) (B) (tan8A)/(tan2A) (C) (cot8A)/(cot2A) (D) none of these

(sec8A-1)/(sec4A-1) is equal to (A) (tan2A)/(tan8A) (B) (tan8A)/(tan2A) (C) (cot8A)/(cot2A) (D) none of these

sec^4x-sec^2x is equal to

(sec8A+sec4A-2)/(sec8A-sec4A) is equal to (A)(tan6A)/(tan10A) (B) (cos10A)/(cos6A)(C)(sin10A)/(sin6A) (D) (tan10A)/(tan6A)

(sec8A-1)/(sec4A-1)=(tan 8A)/(tan2A)

sec^4 A− sec^ 2 A is equal to

sec^(4)x-sec^(2)x is equal to