[33.,217x+131y=913],[131x+217y,=827]

If 217x + 131y = 913, 131x + 217y = 827, then x + y is

Solve: 217x+131y=913131x+217y=827

Solve for x and y {:(217x + 131y = 913),(131x + 217y = 827):}

Solve: 217 x+131 y=913 131 x+217 y=827

Evaluate x + y, if 217x + 131y = 913 and 131x + 217y = 827.

The equation [1 x y][(1,3,1),(0,2,-1),(0,2,-1)] [(1),(x),(y)]=[0] has

Study the following information to answer the given questions. Input: 46, 185, 310,436, 96, 217, 39 Step I: 436, 46, 185,310,96,217,39 Step II: 436, 39, 46, 185,310,96,217 Step III:436, 39, 310,46, 185,96,217 Step IV: 436,39,310,46, 217, 185,96 Step V: 436,39,310,46, 217,96,185 This is the final arrangement and Step V is the last step for this input. Following is the step IV for an input. What will be the first step for the input? Step IV: 726, 19, 537, 33,412, 315, 115, 47, 81