The orbit velocity of a satellite at a height `R` above the surface of Earth is `v`. The escape velocity from the location is

The orbital velocity of a body at height h above the surface of Earth is 36% of that near the surface of the Earth of radius R. If the escape velocity at the surface of Earth is 11.2 km s^-1 , then its value at the height h will be

The orbital velocity of a body at height h above the surface of Earth is 36% of that near the surface of the Earth of radius R. If the escape velocity at the surface of Earth is 11.2 km s_(-1) , then its value at the height h will be

If v_0 be the orbital velocity of a satellite in a circular orbit close to the earth's surface and v_e is the escape velocity from the earth, then relation between the two is .........

If v_(0) be the orbital velocity of a satellite in a circular orbit close to the earth's surface and v_(e) is the escape velocity from the earth , then relation between the two is

If v_(0) be the orbital velocity of a satellite in a circular orbit close to the earth's surface and v_(e) is the escape velocity from the earth , then relation between the two is

sqrt((GM)/(R+h)) : critical velocity of a satellite at height h from surface of planet : : ……………… : escape velocity on the surface of planet

sqrt((GM)/(R+h)) : critical velocity of a satellite at height h from surface of planet : : ……………… : escape velocity on the surface of planet