If `.^(n)C_(r-1) = 36, .^(n)C_(r) = 84` and `.^(n)C_(r+1) = 126`

If .^(n)C_(r-1)=36,.^(n)C_(r)=84and.^(n)C_(r+1)=126 find n and r .

If .^(n)C_(r )=84, .^(n)C_(r-1)=36 " and" .^(n)C_(r+1)=126 , then find the value of n.

IF ""^(n) C_((r-1))=36 ,""^(n)C_(r)=84 , ""^(n)C_(r+1)=126 , then r=

If .^(n+1)C_(r+1): .^(n)C_(r)=11:6 and .^(n)C_(r): .^(n-1)C_(r-1)=6:3 , find n and r.

""^(n) C_(r-1) = 330 ,""^(n)C_(r)=462 , ""^(n)C_(r+1) = 462 implies r=

Prove that: (i) r.^(n)C_(r) =(n-r+1).^(n)C_(r-1) (ii) n.^(n-1)C_(r-1) = (n-r+1) .^(n)C_(r-1) (iii) .^(n)C_(r)+ 2.^(n)C_(r-1) +^(n)C_(r-2) =^(n+2)C_(r) (iv) .^(4n)C_(2n): .^(2n)C_(n) = (1.3.5...(4n-1))/({1.3.5..(2n-1)}^(2))

If ^(n)C_(r)=84,quad nC_(r-1)=36, and ^(n)C_(r+1)=126 then find the value of n.

If ""^(n) C_(r-1) = 36 and ""^(n) C_(r ) = 84 , then a) 13r-3n-3=0 b) 10r-3n-3=0 c) 10r+ 3n-3=0 d) 10r-3n+ 3=0

If nC_(r-1)=36,nC_(r)=84 and nC_(r+1)=126 then (a) n=8,r=4( b) n=9,r=3(c)n=7,r=5(d) non of these