The equation of the circle having x-y-2=...

The equation of the circle having x-y-2=0 and x-y+2=0 as two langents and x-y=0 as diameter, is

`x^2 + y^2 + 2x - 2y +1 = 0`

`x^2 + y^2 -2x + 2y - 1 = 0`

`x^2 + y^2 = 2`

`x^2 + y^2 = 1`

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