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tan^(-1)1+tan^(-1)2+tan^(-1)3=...

`tan^(-1)1+tan^(-1)2+tan^(-1)3=`

A

0

B

`pi`

C

`pi/2`

D

None of these

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tan^(-1)2-tan^(-1)1=tan^(-1)(1/3)

tan^(-1)2-tan^(-1)1=tan^(-1)(1/3)

tan^(-1)2-tan^(-1)1=tan^(-1)(1/3)

tan^(-1)3-tan^(-1)2=tan^(-1)(1/7)

tan^(-1)3-tan^(-1)2=tan^(-1)(1/7)

tan^(-1)1+tan^(-1)1/3=?

If tan^(-1) 3 +tan^(-1)x=tan^(-1)8 then x =

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