Circles x^2 + y^2 = 4 and x^2 + y^2 -2x ...

Circles `x^2 + y^2 = 4` and `x^2 + y^2 -2x -4y +3 = 0`

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The two circles x^(2)+y^(2)-5=0 and x^(2)+y^(2)-2x-4y-15=0

Three sides of a triangle are represented by lines whose combined equation is (2x+y-4) (xy-4x-2y+8) = 0 , then the equation of its circumcircle will be : (A) x^2 + y^2 - 2x - 4y = 0 (B) x^2 + y^2 + 2x + 4y = 0 (C) x^2 + y^2 - 2x + 4y = 0 (D) x^2 + y^2 + 2x - 4y = 0

Two circles x^(2) + y^(2) - 2x - 4y = 0 and x^(2) + y^(2) - 8y - 4 = 0

The equation of the circle passing through the point of intersection of the circles x^(2)+y^(2)-4x-2y=8 and x^(2)+y^(2)-2x-4y=8 and (-1,4) is (a)x^(2)+y^(2)+4x+4y-8=0(b)x^(2)+y^(2)-3x+4y+8=0(c)x^(2)+y^(2)+x+y=0(d)x^(2)+y^(2)-3x-3y-8=0

The locus of the centers of the circles which cut the circles x^(2) + y^(2) + 4x – 6y + 9 = 0 and x^(2) + y^(2) – 5x + 4y – 2 = 0 orthogonally is

Equation of radical axis of the circles x^(2) + y^(2) - 3x - 4y + 5 = 0 and 2x^(2) + 2y^(2) - 10x - 12y + 12 = 0 is

IPUCET PREVIOUS YEAR PAPERS-GGSIPU MATHMATICS 2012-MCQs

If the lines x-y-1=0, 4x+3y=k and 2x-3y+1=0 are concurrent, then k is
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Circles x^2 + y^2 = 4 and x^2 + y^2 -2x -4y +3 = 0
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