The osmotic pressure of 0.2 molar solution of urea at `300 K(R = 0.082)` litre atm `mol^(-1)K^(-1)` is

The osmotic pressure of 0.2 molar solution of urea at 27^@C (R=0.082 litre atm "mol"^(-1) K^(-1)) is

Find out the osmotic pressure of 0.25 M aqueous solution of urea at 27^(@)C (R = 0.082 " litre atm K"^(-1) "mol"^(-1),R=1.987 "cal K"^(-1) "mol"^(-1))

What is meant by the molarity of a solution ? What would be the osmotic pressure of a 0.02 molar aqueous solution of urea at 27^(@)C ? (R = 0.082 L.atm.K^(-1). Mol^(-1) )

Calculate the osmotic pressure of 0.05% urea solution in water at 20^(@) C. Given R = 0.0821 atm mol^(-1)K^(-1) . Molar mass of urea = 60 g mol^(-1) .

Find the osmotic pressure M/20 solution of urea at 27^(@)C (S = 0.0821 lit atm K^(-1) mol^(-1))

Calculate the osmotic pressure of a 10%. Solution of glucose at 18^@C . R = 0.082 lit atm K^-1 mol^-1 .

Find out the osmotic pressure of 0.25 M aqueous solution of Urea at 27^@ C. (R = 0.082 Lit. atm./mol. K., R = 1.987 Cal.)