If `s=4t+(1)/(t)` is the equation o motion of a particle, then the acceleration when velocity vanishes, is

Options

A. 0
B. 16
C. 8
D. 1

Answer

B

Explanation

We have,
`s=4t+(1)/(t)implies(ds)/(dt)=4-(1)/(t^(2))and (d^(2)s)/(dt^(2))=(2)/(t^(3))`
Now,
Velocity = `0 implies (ds)/(dt)=0implies 4-(1)/(t^(2))=0impliest=(1)/(2)`
`therefore ("Acceleration at t ="(1)/(2))=((d^(2)s)/(dt^(2)))_(t=(1)/(2))=(2)/(((1)/(2))^(3))=16`