" 18.If "Delta=|[1,sin theta,1],[-sin theta,1,sin theta],[-1,-sin theta,1]|," then find range of "Delta" ."

let Delta=det[[1,sin theta,1-sin theta,1,sin theta-1,-sin theta,1]],0<=theta<=2 pi

Let Delta=|(1,sin theta, 1),(-sin theta, 1, sin theta),(-1,-sin theta,1)|0,le theta le 2pi . The

If Delta=|(1, sin theta, 1 ),(-sin theta, 1, sin theta),(-1 , -sin theta, 1)| then Delta lies in the interval

Let Delta(theta)=|(1, sin theta, 1),(sin theta, 1, sin theta),(-1, -sin theta , 1)|, 0 le theta le 2pi solution of Delta(theta)=3 is

If Delta=det[[1,3cos theta,1sin theta,1,3cos theta1,sin theta,1]], then the 1000, l|maximum value of Delta- minimum value of Delta|^(3)] is equal to.

A = [(cos theta,-sin theta),(-sin theta,-cos theta)] then find A^(-1) .

If Delta=|(1,3cos theta,1),(sin theta,1,3cos theta),(1,sin theta,1)|, then the 1/1000 [|maximum value of Delta- minimum value of Delta|^3 ] is equal to.

cos theta/(1+sin theta)=(1-sin theta)/cos theta

(sin theta)/(1-cos theta)=(1+cos theta)/(sin theta)