A parallel plate capacitor with a dielectric slab with dielectric constant `k= 3` filling the space between the plates is charged to potential `V` and isolated. Then the dielectric slab is drawn out and another dielectric slab of equal thickness but dielectric constant `k'= 2` is introduced between the plates. The ratio of the energy stored in the capacitor later to that initially is:

A parallel plate capacitor carries a harge Q. If a dielectric slab with dielectric constant K=2 is dipped between the plates, then

A charged parallel plate capacitor has a potential energy U. if a slab of dielectric constant k is inserted between the plates, then the new potential energy will be_

If a dielectric slab of thickness 5 mm and dielectric constant K=6 is introduced between the plates of a parallel plate air capacitor, with plate separation of 8 mm, then its capacitance is

The separation between the plates of a parallel plate capacitor is d and the area of each plate is A. iff a dielectric slab of thickness x and dielectric constant K is introduced between the plates, then the capacitance will be

A parallel plate capacitor has a capacitance of 2muF . A slab of dielectric constant 5 is inserted between the plates and the capaitor is charged to 100 V and then isolated. How much work is required to remove the dielectric slab?

A parallel plate capacitor has a capacitance of 2muF . A slab of dielectric constant 5 is inserted between the plates and the capaitor is charged to 100 V and then isolated. What is the new potential difference, if the dielectric slab is removed?

A dielectric slab is introduced between the plates of a capacitor. Then the potential difference and the capacity respectively

Capacity of a capacitor is 3muF . A slab of dielectric constant 4 is inserted between the plates and capacitor is charged to 200V and then isolated. What is the new potential difference if the dielectric slab is removed?

Separation between the plates of parallel plate capacitor is 5 mm. this capacitor, having air as the dielectric medium between the plates, is charged to a potential difference 25 V using a battery. The battery is then disconnected and a dielectric slab of thickness 3mm and dielectric constant K=10 is placed between the plates as shown. potential difference between the plates after the dielectric slab has been introduced is-