If `alpha = (2pi)/7`, then `tan alpha tan 2alpha + tan 2alpha tan 4alpha + tan 4alpha tan alpha =`

If alpha = (2pi )/(7) , then tan alpha tan 2 alpha + tan 2 alpha tan 4 alpha + tan 4 alpha tan alpha =

If alpha = (2pi)/7 prove that tan alpha *tan 2alpha + tan 2alpha* tan 4alpha + tan 4alpha* tan a = - 7

If alpha=(2 pi)/(7), then tan alpha tan2 alpha+tan2 alpha tan4 alpha+tan4 alpha tan alpha

If alpha=(2 pi)/(7) then tan alpha tan^(7)2 alpha+tan2 alpha tan4 alpha+tan2 alpha tan4 alpha=

" If "alpha=(2 pi)/(7)" ,and "tan alpha tan2 alpha+tan2 alpha tan4 alpha+tan4 alpha tan alpha=K" .Then "3k^(2)+4k+5=" ."

tan alpha + 2 tan 2alpha + 4 tan 4 alpha + 8 cot 8 alpha =

tan alpha + 2 tan 2alpha + 4 tan 4 alpha + 8 cot 8 alpha =

" If alpha=(2 pi)/(7) ,then the value of tan alpha tan2 alpha+tan2 alpha tan4 alpha+tan4 alpha tan alpha is "

If alpha=(pi)/(14), then the value of (tan alpha tan2 alpha+tan2 alpha tan4 alpha+tan4 alpha tan alpha) is 1(b)1/2(c)2(d)1/3