CB perp CD*" If "AQ=BP" and "DP=CQ" prove that "

In Figure,AD perp CD and CB perp c. If AQ=BP and DP=CQ, prove that /_DAQ=/_CBP .

In the fig. ADbotCD and CBbotCD . If AQ=BP and DP=CQ prove that angleDAQ=angleCBP .

Q.in fig DB perp BC,DE perp AB and AC perp BC prove that (BE)/(DE)=(AC)/(BC)

In Fig.4.145, if AB perp BC,DC perp BC and DE perp AC, prove that CEDABC. (FIGURE)

In a ABC,AD perp BC and AD^(2)=BD xx CD prove that ABC is a right triangle.

In Figure , If PQ || BC and PR || CD, prove that (QB)/(AQ)=(DR)/(AR) .

In Figure , If PQ || BC and PR || CD, prove that (QB)/(AQ)=(DR)/(AR) .

ABCD is a square M is the mid point of AB . PQbotCM . PQ meets AD at P and CB at Q prove that CP=CQ

In a ABC, AD perp BC and AD^(2)=BD xx CD .Prove that ABC is a right triangle.

ABCD is a trapezium such that AB and CD are parallel and BC perp CD. If /ADB= theta BC=p and CD=q', then AB is equal to