निम्नलिखित का मान बताइये :
`sin A * cos B - cos A * sin B " यदि " tan A = sqrt 3 " और " sin B = 1/2`

If sin A=a cos B and cos A=b sin B then tan^(2)B =

(sin A + sin B) / (cos A + cos B) = tan ((A + B) / (2))

If sin A + sin B = sqrt (3) (cos B-cos A) then sin3A + sin3B =

If sin A + sin B = sqrt (3) (cos B-cos A) then sin3A + sin3B =

sin A + sin B = sqrt(3) ( cos B- cos A )implies sin 3A + sin 3B=

sin 2A + sin 2B + sin 2 (A-B)= A) 4 sin A * sin B * sin (A-B) B) 4 sin A * cos B * cos (A-B) C) 4 cos A * sin B * cos (A-B) D) 4 cos A * cos B * sin (A-B)

(sin ^ (2) A-sin ^ (2) B) / (sin A cos A-sin B cos B) = tan (A + B)

Prove that (sin A-sin B)/(cos A+ cos B) = "tan" (A-B)/2

sqrt (2) cos A = cos B + cos ^ (3) Bsqrt (2) sin A = sin B-sin ^ (3) B, find sin (AB)