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Vandana bought a watch for X 600 and sol...

Vandana bought a watch for X 600 and sold it the same day for X 688.50 at a credit of 9 months and this way she gained 2%. Find the rate of interest per annum.

A

`16(2)/(3)%`

B

`15(2)/(3)%`

C

`11(2)/(3)%`

D

`5(2)/(3)%`

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The correct Answer is:
To solve the problem step by step, we will follow the given information and apply the formulas related to true discount and interest rates. ### Step 1: Identify the Cost Price and Selling Price Vandana bought the watch for ₹600 and sold it for ₹688.50. ### Step 2: Calculate the Gain The gain can be calculated as: \[ \text{Gain} = \text{Selling Price} - \text{Cost Price} = 688.50 - 600 = ₹88.50 \] ### Step 3: Calculate the Gain Percentage The gain percentage is given as 2%. We can express this as: \[ \text{Gain Percentage} = \frac{\text{Gain}}{\text{Cost Price}} \times 100 \] From the problem, we know: \[ 2 = \frac{88.50}{600} \times 100 \] This confirms that the gain is indeed 2%. ### Step 4: Calculate the Present Worth Since Vandana sold the watch on credit for 9 months, we need to find the present worth (PW) of the selling price. The present worth can be calculated as: \[ \text{Present Worth} = \text{Selling Price} - \text{Gain} = 688.50 - 88.50 = ₹600 \] ### Step 5: Calculate the True Discount The true discount (TD) is the difference between the present worth and the cost price: \[ \text{True Discount} = \text{Selling Price} - \text{Present Worth} = 688.50 - 600 = ₹88.50 \] ### Step 6: Set Up the True Discount Formula The formula for true discount is given by: \[ TD = \frac{\text{Present Worth} \times R \times T}{100} \] Where: - TD = True Discount - Present Worth = ₹600 - R = Rate of interest per annum (unknown) - T = Time in years = \( \frac{9}{12} = \frac{3}{4} \) years Substituting the known values into the formula: \[ 88.50 = \frac{600 \times R \times \frac{3}{4}}{100} \] ### Step 7: Solve for R Rearranging the equation to solve for R: \[ 88.50 \times 100 = 600 \times R \times \frac{3}{4} \] \[ 8850 = 600 \times R \times \frac{3}{4} \] \[ 8850 = 450R \] \[ R = \frac{8850}{450} = 19.67\% \] ### Final Answer The rate of interest per annum is approximately **19.67%**. ---
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