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A pipe can fill a cistern in 12 min and ...

A pipe can fill a cistern in 12 min and another pipe can fill it in 15 min, but a third pipe can empty it in 6 min. The first two pipes are kept open for 5 min in the beginning and then the third pipe is also opened. Time taken to empty the cistern is

A

38 min

B

22 min

C

42 min

D

45min

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will analyze the filling and emptying rates of the pipes involved. ### Step 1: Determine the rates of the pipes 1. **First Pipe**: Fills the cistern in 12 minutes. - Rate = \( \frac{60 \text{ units}}{12 \text{ min}} = 5 \text{ units/min} \) 2. **Second Pipe**: Fills the cistern in 15 minutes. - Rate = \( \frac{60 \text{ units}}{15 \text{ min}} = 4 \text{ units/min} \) 3. **Third Pipe**: Empties the cistern in 6 minutes. - Rate = \( -\frac{60 \text{ units}}{6 \text{ min}} = -10 \text{ units/min} \) ### Step 2: Calculate the total units filled in the first 5 minutes - In 1 minute, the first two pipes together fill: - \( 5 \text{ units/min} + 4 \text{ units/min} = 9 \text{ units/min} \) - In 5 minutes, they will fill: - \( 9 \text{ units/min} \times 5 \text{ min} = 45 \text{ units} \) ### Step 3: Calculate the remaining units after 5 minutes - After 5 minutes, the cistern has: - \( 60 \text{ units} - 45 \text{ units} = 15 \text{ units} \) remaining to be filled. ### Step 4: Determine the net rate when all three pipes are open - When all three pipes are open, the net rate is: - \( 5 \text{ units/min} + 4 \text{ units/min} - 10 \text{ units/min} = -1 \text{ unit/min} \) ### Step 5: Calculate the time taken to empty the remaining units - Since the net rate is -1 unit/min, it means the cistern is emptying at a rate of 1 unit per minute. - To empty the remaining 15 units: - Time = \( \frac{15 \text{ units}}{1 \text{ unit/min}} = 15 \text{ minutes} \) ### Step 6: Total time taken to empty the cistern - The total time taken to empty the cistern after the first 5 minutes is: - \( 5 \text{ minutes} + 15 \text{ minutes} = 20 \text{ minutes} \) Thus, the total time taken to empty the cistern after the third pipe is opened is **20 minutes**. ---
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ARIHANT SSC-PIPES AND CISTERNS -EXERCISE HIGHER SKILL LEVEL QUESTION
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  15. Two taps A and B can fill a tank in 25min and 20 min , respectively , ...

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  16. Two taps A and B can fill a tank in 20 min and 30 min, respectively. A...

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