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A tank can be filled by a tap in 20 min ...

A tank can be filled by a tap in 20 min and by another tap in 60 min. Both the taps are kept open for 5 min and then the 1st tap is shut off. After this, how much time the tank will be completely filled?

A

20 min

B

30 min

C

45min

D

40 min

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we can follow these calculations: ### Step 1: Determine the filling rates of both taps. - **Tap 1** fills the tank in 20 minutes. Therefore, its filling rate is: \[ \text{Rate of Tap 1} = \frac{1 \text{ tank}}{20 \text{ min}} = \frac{3 \text{ units}}{1 \text{ min}} \quad (\text{assuming tank capacity is 60 units}) \] - **Tap 2** fills the tank in 60 minutes. Therefore, its filling rate is: \[ \text{Rate of Tap 2} = \frac{1 \text{ tank}}{60 \text{ min}} = \frac{1 \text{ unit}}{1 \text{ min}} \] ### Step 2: Calculate the combined filling rate when both taps are open. - When both taps are open, the combined filling rate is: \[ \text{Combined Rate} = \text{Rate of Tap 1} + \text{Rate of Tap 2} = 3 \text{ units/min} + 1 \text{ unit/min} = 4 \text{ units/min} \] ### Step 3: Calculate the amount of water filled in the first 5 minutes. - In 5 minutes, the amount of water filled by both taps is: \[ \text{Water filled in 5 min} = \text{Combined Rate} \times 5 \text{ min} = 4 \text{ units/min} \times 5 \text{ min} = 20 \text{ units} \] ### Step 4: Determine the remaining capacity of the tank. - Since the total capacity of the tank is 60 units, the remaining capacity after 5 minutes is: \[ \text{Remaining Capacity} = 60 \text{ units} - 20 \text{ units} = 40 \text{ units} \] ### Step 5: Calculate the time taken by Tap 2 to fill the remaining capacity. - After 5 minutes, Tap 1 is shut off, and only Tap 2 is left to fill the remaining 40 units. Since Tap 2 fills at a rate of 1 unit per minute, the time taken to fill the remaining capacity is: \[ \text{Time taken by Tap 2} = \frac{\text{Remaining Capacity}}{\text{Rate of Tap 2}} = \frac{40 \text{ units}}{1 \text{ unit/min}} = 40 \text{ minutes} \] ### Final Answer: - Therefore, the total time taken to fill the tank completely after both taps are opened for 5 minutes and then Tap 1 is shut off is: \[ \text{Total Time} = 5 \text{ minutes} + 40 \text{ minutes} = 45 \text{ minutes} \]
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ARIHANT SSC-PIPES AND CISTERNS -EXERCISE HIGHER SKILL LEVEL QUESTION
  1. A tap having diameter 'd' cam empty a tank in 40 min . How long anothe...

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  2. Two pipes can fill a cistern in 14 and 16 h, respectively. The pipes a...

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  3. Two pipes A and B can fill a tank in 24 and 32 min, respectively. If b...

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  4. Two pipes A and B can fill acistern in 15 and 20min, respectively. Bot...

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  5. A pipe can fill a cistern in 12 min and another pipe can fill it in 15...

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  6. A tank can be filled by a tap in 20 min and by another tap in 60 min. ...

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  7. A cistern has three pipes A,B and C. Pipes Aand B can fill it in 3 and...

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  8. If two pipes function together, the tank will be filled in 12 h. One p...

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  9. A pipe P can fill a tank in 12 min and another pipe R can fill it in 1...

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  10. Three pipes A, B and C can fill a tank in 30 min, 20 min and 10 min, r...

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  11. There are 7 pipes attached with a tank out of which some are inlets an...

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  12. Capacity of tap B is 80% more than that of A.If both the taps are open...

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  13. Three taps A,B and C fill a tank in 20 min, 15 min and 12 min, respect...

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  14. Taps A,B and C are attached with a tank and velocity of water coming t...

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  15. Two taps A and B can fill a tank in 25min and 20 min , respectively , ...

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  16. Two taps A and B can fill a tank in 20 min and 30 min, respectively. A...

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  17. There are three taps of diameters 1cm, 4/3 cm and 2 cm , respectively ...

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