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How many different signals, can be made ...

How many different signals, can be made by 5 flags from 8 flags of different colours?

A

(1) 6270

B

(2) 1680

C

(3) 20160

D

(4) 6720

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of how many different signals can be made by using 5 flags from a total of 8 flags of different colors, we will use the concept of permutations since the order in which the flags are arranged matters. ### Step-by-Step Solution: 1. **Identify the Total Flags and Flags to Choose**: - We have a total of \( n = 8 \) flags. - We need to choose \( r = 5 \) flags. 2. **Use the Permutation Formula**: - The formula for permutations is given by: \[ P(n, r) = \frac{n!}{(n - r)!} \] - Here, \( n! \) (n factorial) is the product of all positive integers up to \( n \), and \( (n - r)! \) is the product of all positive integers up to \( n - r \). 3. **Substitute the Values into the Formula**: - Substitute \( n = 8 \) and \( r = 5 \) into the formula: \[ P(8, 5) = \frac{8!}{(8 - 5)!} = \frac{8!}{3!} \] 4. **Calculate \( 8! \) and \( 3! \)**: - \( 8! = 8 \times 7 \times 6 \times 5 \times 4 \times 3! \) - \( 3! = 3 \times 2 \times 1 = 6 \) 5. **Simplify the Expression**: - Now, we can cancel \( 3! \) in the numerator and denominator: \[ P(8, 5) = \frac{8 \times 7 \times 6 \times 5 \times 4 \times 3!}{3!} = 8 \times 7 \times 6 \times 5 \times 4 \] 6. **Perform the Multiplication**: - Calculate \( 8 \times 7 = 56 \) - Next, \( 56 \times 6 = 336 \) - Then, \( 336 \times 5 = 1680 \) - Finally, \( 1680 \times 4 = 6720 \) 7. **Final Answer**: - Therefore, the total number of different signals that can be made by using 5 flags from 8 flags of different colors is: \[ \boxed{6720} \]
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