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In how many ways, 12 balls can be divide...

In how many ways, 12 balls can be divided between 2 boys, one receiving 5 and the other 7 balls?

A

1784

B

1584

C

1854

D

1560

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of how many ways 12 balls can be divided between 2 boys, where one boy receives 5 balls and the other receives 7 balls, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Total Number of Balls**: We have a total of 12 balls. 2. **Determine the Distribution**: One boy (let's call him Boy A) will receive 5 balls, and the other boy (Boy B) will receive 7 balls. 3. **Calculate the Number of Ways to Choose Balls for Boy A**: The number of ways to choose 5 balls out of 12 can be calculated using the combination formula: \[ \binom{n}{r} = \frac{n!}{r!(n-r)!} \] Here, \( n = 12 \) and \( r = 5 \): \[ \binom{12}{5} = \frac{12!}{5!(12-5)!} = \frac{12!}{5! \cdot 7!} \] 4. **Simplify the Combination**: We can simplify \( \frac{12!}{5! \cdot 7!} \): \[ \binom{12}{5} = \frac{12 \times 11 \times 10 \times 9 \times 8}{5 \times 4 \times 3 \times 2 \times 1} \] 5. **Calculate the Numerator**: Calculate the product in the numerator: \[ 12 \times 11 = 132 \] \[ 132 \times 10 = 1320 \] \[ 1320 \times 9 = 11880 \] \[ 11880 \times 8 = 95040 \] 6. **Calculate the Denominator**: Calculate \( 5! \): \[ 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \] 7. **Final Calculation**: Now divide the numerator by the denominator: \[ \frac{95040}{120} = 792 \] 8. **Consider Both Cases**: Since Boy A can receive either 5 balls or 7 balls, we multiply the result by 2 (for the two different distributions): \[ 792 \times 2 = 1584 \] ### Final Answer: Thus, the total number of ways to distribute the 12 balls between the two boys is **1584**.
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