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The value of cos 20^(@) cos 40^(@)cos 60...

The value of `cos 20^(@) cos 40^(@)cos 60^(@) cos 80^(@)` is equal to

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The correct Answer is:
`1/16`
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cos 20^(@) cos 40^(@) cos 80^(@)=

The value of cos40^(@)+cos80^(@)+cos160^(@) is

cos20^(@).cos40^(@).cos60^(@).cos80^(@) is :

cos40^(@)+cos 80^(@)+cos160^(@)+cos240^(@) =

The value of cos 20^(@) + Cos 100^(@) + cos 140^(@) is

Statement-1: The vlaue of cos20^(@)cos40^(@)cos60^(@)cos80^(@)is1/16. Statement-2: for any theta, cos thetacos(60^(@)-theta)cos(60^(@)+theta)=1/4cos3theta

cos20 ^ (@). cos40 ^ (@). cos60 ^ (@) cos80 ^ (@) =

ARIHANT SSC-TRIGONOMETRY-EXERCISE(LEVEL - 1)
  1. The value of cos 20^(@) cos 40^(@)cos 60^(@) cos 80^(@) is equal to

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  2. If 0lt theta lt 90^(@), the (sin theta+cos theta) is :

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  3. The value of x satisfying the equation sinx+(1)/(sinx)=(7)/(2sqrt(3)) ...

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  4. If sintheta-cos theta=0 and 0 lt theta le pi//2. then theta is equal t...

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  5. Given that theta is acute and then sin theta=(3)/(5). Let x, y be posi...

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  6. Which one of the following pairs is correctly matched?

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  7. If xtan45^(@).cos60^(@)=sin60^(@)cot60^(@), then x is equal to

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  8. If theta lies in the second quadrant, then sqrt((1-sintheta)/(1+sin th...

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  9. sin^(6)A+cos^(6)A is equal to :

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  10. If sec x=P, " cosec "x=Q, then :

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  11. sin^(2)Acos^(2)B-cos^(2)A sin^(2)B simplifies to :

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  12. If sin2x=n sin 2y, then the value of (tan(x+y))/(tan(x-y)) is :

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  13. The least value of 2sin^2theta+3cos^2theta is 1 (b) 2 (c) 3 (d) ...

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  14. The value of tan(180+theta).tan (90-theta) is :

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  15. log tan 1^@+log tan2^@+log tan3^@+...log tan89^@=

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  16. If we convert sin(-566^(@)) to same trigonometrical ratio of a positiv...

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  17. From the Masthead of a ship, the angle of Depression of boat is 60^@, ...

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  18. A portion of a 30 m long tree is broken by tornado and the top struck ...

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  19. Two posts are 25 m and 15 m high and the line joining their tips makes...

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  20. The angle of elevation of the top of a tower at a point G on the groun...

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  21. If x=sec theta+tan theta, y = sec theta-tan theta, then the relation b...

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