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If (sec theta + tan theta)/(sec theta - ...

If `(sec theta + tan theta)/(sec theta - tan theta) = 5/3`, then `sin theta` is equal to

A

`2//3`

B

`3//4`

C

`1//4`

D

`1//3`

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The correct Answer is:
To solve the equation \(\frac{\sec \theta + \tan \theta}{\sec \theta - \tan \theta} = \frac{5}{3}\), we will follow these steps: ### Step 1: Rewrite sec and tan in terms of sin and cos We know that: \[ \sec \theta = \frac{1}{\cos \theta} \quad \text{and} \quad \tan \theta = \frac{\sin \theta}{\cos \theta} \] Substituting these into the equation gives: \[ \frac{\frac{1}{\cos \theta} + \frac{\sin \theta}{\cos \theta}}{\frac{1}{\cos \theta} - \frac{\sin \theta}{\cos \theta}} = \frac{5}{3} \] ### Step 2: Simplify the equation The equation simplifies to: \[ \frac{\frac{1 + \sin \theta}{\cos \theta}}{\frac{1 - \sin \theta}{\cos \theta}} = \frac{5}{3} \] This can be further simplified by canceling \(\cos \theta\) (assuming \(\cos \theta \neq 0\)): \[ \frac{1 + \sin \theta}{1 - \sin \theta} = \frac{5}{3} \] ### Step 3: Cross-multiply to eliminate the fraction Cross-multiplying gives: \[ 3(1 + \sin \theta) = 5(1 - \sin \theta) \] ### Step 4: Expand both sides Expanding both sides results in: \[ 3 + 3\sin \theta = 5 - 5\sin \theta \] ### Step 5: Combine like terms Rearranging the equation to combine all \(\sin \theta\) terms on one side gives: \[ 3\sin \theta + 5\sin \theta = 5 - 3 \] This simplifies to: \[ 8\sin \theta = 2 \] ### Step 6: Solve for \(\sin \theta\) Dividing both sides by 8 gives: \[ \sin \theta = \frac{2}{8} = \frac{1}{4} \] ### Final Answer Thus, the value of \(\sin \theta\) is: \[ \sin \theta = \frac{1}{4} \] ---
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