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If tan theta = 4/3,then the value of (3 ...

If `tan theta = 4/3`,then the value of `(3 sin theta + 2cos theta)/(3 sin theta - 2 cos theta)` is

A

0.5

B

`-0.5`

C

3

D

`-3.0`

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The correct Answer is:
To solve the problem, we start with the given information that \( \tan \theta = \frac{4}{3} \). We need to find the value of \[ \frac{3 \sin \theta + 2 \cos \theta}{3 \sin \theta - 2 \cos \theta}. \] ### Step 1: Express \(\sin \theta\) and \(\cos \theta\) in terms of \(\tan \theta\) Since \( \tan \theta = \frac{\sin \theta}{\cos \theta} \), we can express \(\sin \theta\) and \(\cos \theta\) using the relationship of sine and cosine with tangent. Let: - \(\sin \theta = 4k\) - \(\cos \theta = 3k\) where \(k\) is a positive constant. ### Step 2: Calculate \(3 \sin \theta\) and \(2 \cos \theta\) Now, substituting the values of \(\sin \theta\) and \(\cos \theta\): \[ 3 \sin \theta = 3(4k) = 12k, \] \[ 2 \cos \theta = 2(3k) = 6k. \] ### Step 3: Substitute into the expression Now we can substitute these into the original expression: \[ \frac{3 \sin \theta + 2 \cos \theta}{3 \sin \theta - 2 \cos \theta} = \frac{12k + 6k}{12k - 6k} = \frac{18k}{6k}. \] ### Step 4: Simplify the expression Now we simplify the fraction: \[ \frac{18k}{6k} = 3. \] ### Conclusion Thus, the value of \[ \frac{3 \sin \theta + 2 \cos \theta}{3 \sin \theta - 2 \cos \theta} = 3. \] ### Final Answer The correct answer is option 3, which is \(3\). ---
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