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Consider the following equations (i) c...

Consider the following equations
(i) `cosec^2 x + sec^2 x = cosec^2 x sec^2 x`
(ii) `sec^2 x + tan^2 x = secx tan^2 x`
(iii) `cosec^2 x+ tan^2x = cot^2x + sec^2x`
Which of the above equations are correct ?

A

(i) and (ii)

B

(ii) and (iii)

C

(i) and (iii)

D

(i), (ii) and (iii)

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the given equations are correct, we will analyze each equation step by step. ### Step 1: Analyze the First Equation The first equation is: \[ \csc^2 x + \sec^2 x = \csc^2 x \sec^2 x \] **Left Hand Side (LHS)**: \[ \csc^2 x + \sec^2 x = \frac{1}{\sin^2 x} + \frac{1}{\cos^2 x} \] To combine these fractions, we need a common denominator: \[ = \frac{\cos^2 x + \sin^2 x}{\sin^2 x \cos^2 x} \] Using the Pythagorean identity \(\sin^2 x + \cos^2 x = 1\): \[ = \frac{1}{\sin^2 x \cos^2 x} = \csc^2 x \sec^2 x \] **Right Hand Side (RHS)**: \[ \csc^2 x \sec^2 x = \frac{1}{\sin^2 x} \cdot \frac{1}{\cos^2 x} = \frac{1}{\sin^2 x \cos^2 x} \] Since LHS = RHS, the first equation is **correct**. ### Step 2: Analyze the Second Equation The second equation is: \[ \sec^2 x + \tan^2 x = \sec x \tan^2 x \] **Left Hand Side (LHS)**: \[ \sec^2 x + \tan^2 x = \frac{1}{\cos^2 x} + \frac{\sin^2 x}{\cos^2 x} = \frac{1 + \sin^2 x}{\cos^2 x} \] Using the identity \(1 + \tan^2 x = \sec^2 x\): \[ = \sec^2 x \] **Right Hand Side (RHS)**: \[ \sec x \tan^2 x = \frac{1}{\cos x} \cdot \frac{\sin^2 x}{\cos^2 x} = \frac{\sin^2 x}{\cos^3 x} \] Since LHS does not equal RHS, the second equation is **incorrect**. ### Step 3: Analyze the Third Equation The third equation is: \[ \csc^2 x + \tan^2 x = \cot^2 x + \sec^2 x \] **Left Hand Side (LHS)**: \[ \csc^2 x + \tan^2 x = \frac{1}{\sin^2 x} + \frac{\sin^2 x}{\cos^2 x} \] Finding a common denominator: \[ = \frac{\cos^2 x + \sin^4 x}{\sin^2 x \cos^2 x} \] **Right Hand Side (RHS)**: \[ \cot^2 x + \sec^2 x = \frac{\cos^2 x}{\sin^2 x} + \frac{1}{\cos^2 x} \] Finding a common denominator: \[ = \frac{\cos^4 x + \sin^2 x}{\sin^2 x \cos^2 x} \] Since both sides simplify to the same expression, the third equation is **correct**. ### Conclusion The correct equations are: - First Equation: Correct - Second Equation: Incorrect - Third Equation: Correct
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