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A man 2.5 m tall is 32.5 m away from a b...

A man 2.5 m tall is 32.5 m away from a building. The angle of elevation of the top of the building from his eyes is `60^@`. What is the height of the building? Also, calculate the distance between the eye of man and top point of the building.

A

5879 m, 65 m

B

60 m, 59.5 m

C

58m, 60 m

D

59.5 m, 60,5 m

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Knowledge Check

  • From two points A and B on the same side of a building the angles of elevation of the top of the building are 30^(@) and 60^(@) respectively. if the height of the building is 10 m find the distances between A and B correct to two decimal places

    A
    10 . 66 m
    B
    13 . 43 m
    C
    11 . 55 m
    D
    12 . 26 m

  • The angle of elevation of the top of a building from the top and bottom of a tree are x and y repectively . If the height of the tree is h metre , then (in metre) the height of the building is

    A
    `(h cotx)/(cotx +coty)`
    B
    `(h cot y)/(cot c +coty)`
    C
    `(h cot x)/(cotx-coty)`
    D
    `(h cot y)/(cotx-coty)`

  • The angles of elevation of the top of a building from the top and bottom of a tree are 30^@ and 60^@ respectively. If the height of the tree is 50 m, then what is the height of the building?

    A
    `50sqrt()3`
    B
    `75`
    C
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    D
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