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Two numbers are less than a third number...

Two numbers are less than a third number by 25 % and 30 % , respectively. How much per cent is the second number less than first number ?

A

`6(1)/(3)` %

B

`6(1)/(4)` %

C

`6(2)/(3)` %

D

`6(3)/(4)` %

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The correct Answer is:
To solve the problem step by step, let's define the variables and follow the logic outlined in the video transcript. ### Step 1: Define the Variables Let: - \( a \) = First number - \( b \) = Second number - \( c \) = Third number ### Step 2: Express the First Number in Terms of the Third Number According to the problem, the first number \( a \) is 25% less than the third number \( c \). We can express this mathematically as: \[ a = c - 0.25c = 0.75c \] This means: \[ a = \frac{3}{4}c \] ### Step 3: Express the Second Number in Terms of the Third Number Similarly, the second number \( b \) is 30% less than the third number \( c \). This can be expressed as: \[ b = c - 0.30c = 0.70c \] Thus: \[ b = \frac{7}{10}c \] ### Step 4: Find the Relationship Between the First and Second Numbers Now we need to find how much percent the second number \( b \) is less than the first number \( a \). We can express this as: \[ \text{Percentage decrease} = \frac{a - b}{a} \times 100 \] ### Step 5: Substitute the Values of \( a \) and \( b \) Substituting the expressions for \( a \) and \( b \): \[ \text{Percentage decrease} = \frac{0.75c - 0.70c}{0.75c} \times 100 \] ### Step 6: Simplify the Expression Now, simplify the numerator: \[ 0.75c - 0.70c = 0.05c \] So, we have: \[ \text{Percentage decrease} = \frac{0.05c}{0.75c} \times 100 \] The \( c \) cancels out: \[ \text{Percentage decrease} = \frac{0.05}{0.75} \times 100 \] ### Step 7: Calculate the Final Value Now, calculate \( \frac{0.05}{0.75} \): \[ \frac{0.05}{0.75} = \frac{5}{75} = \frac{1}{15} \] Thus: \[ \text{Percentage decrease} = \frac{1}{15} \times 100 = \frac{100}{15} = 6.67\% \] ### Step 8: Final Result The second number is approximately \( 6.67\% \) less than the first number. ---
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