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If (1 + tan A) (1 + tanB) = 2, then { ...

If (1 + tan A) (1 + tanB) = 2, then { A + B) is equal to

A

`pi/2`

B

`pi/3`

C

`pi/4`

D

`pi/6`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the equation \( (1 + \tan A)(1 + \tan B) = 2 \) and find the value of \( A + B \), we can follow these steps: ### Step 1: Expand the left-hand side We start by expanding the left-hand side of the equation: \[ (1 + \tan A)(1 + \tan B) = 1 + \tan A + \tan B + \tan A \tan B \] So, we can rewrite the equation as: \[ 1 + \tan A + \tan B + \tan A \tan B = 2 \] ### Step 2: Simplify the equation Next, we simplify the equation by subtracting 1 from both sides: \[ \tan A + \tan B + \tan A \tan B = 1 \] ### Step 3: Use the tangent addition formula We know that: \[ \tan(A + B) = \frac{\tan A + \tan B}{1 - \tan A \tan B} \] From our equation, we can see that: \[ \tan A + \tan B = 1 - \tan A \tan B \] Substituting this into the tangent addition formula gives us: \[ \tan(A + B) = \frac{1 - \tan A \tan B}{1 - \tan A \tan B} \] This simplifies to: \[ \tan(A + B) = 1 \] ### Step 4: Solve for \( A + B \) The equation \( \tan(A + B) = 1 \) implies that: \[ A + B = 45^\circ \quad \text{(or any angle of the form \( 45^\circ + n \cdot 180^\circ \))} \] ### Step 5: Convert to radians Since the question may require the answer in radians, we convert \( 45^\circ \) to radians: \[ A + B = 45^\circ = \frac{\pi}{4} \text{ radians} \] ### Final Answer Thus, we conclude that: \[ A + B = \frac{\pi}{4} \]
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