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The ratio between the number of sides of...

The ratio between the number of sides of two regular Polygons is 1:2 and ratio between their interior angles is 2 : 3, The number of sides of these polygons are respectively

A

7,4

B

6,12

C

5,10

D

4,8

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The correct Answer is:
To solve the problem, we need to find the number of sides of two regular polygons given their ratios of sides and interior angles. ### Step-by-Step Solution: 1. **Define Variables**: Let \( n_1 \) be the number of sides of the first polygon and \( n_2 \) be the number of sides of the second polygon. According to the problem, the ratio of the number of sides is given as: \[ \frac{n_1}{n_2} = \frac{1}{2} \] This means: \[ n_2 = 2n_1 \] 2. **Interior Angle Formula**: The formula for the interior angle of a regular polygon with \( n \) sides is: \[ \text{Interior Angle} = \frac{(n-2) \times 180}{n} \] Thus, for the first polygon: \[ \text{Interior Angle}_1 = \frac{(n_1 - 2) \times 180}{n_1} \] And for the second polygon: \[ \text{Interior Angle}_2 = \frac{(n_2 - 2) \times 180}{n_2} \] 3. **Set Up the Ratio of Interior Angles**: We know the ratio of the interior angles is given as: \[ \frac{\text{Interior Angle}_1}{\text{Interior Angle}_2} = \frac{2}{3} \] Substituting the expressions for the interior angles: \[ \frac{\frac{(n_1 - 2) \times 180}{n_1}}{\frac{(n_2 - 2) \times 180}{n_2}} = \frac{2}{3} \] This simplifies to: \[ \frac{(n_1 - 2) \times n_2}{(n_2 - 2) \times n_1} = \frac{2}{3} \] 4. **Substituting \( n_2 \)**: Substitute \( n_2 = 2n_1 \) into the equation: \[ \frac{(n_1 - 2) \times (2n_1)}{(2n_1 - 2) \times n_1} = \frac{2}{3} \] Simplifying the left side: \[ \frac{2(n_1 - 2)}{2 - \frac{2}{n_1}} = \frac{2}{3} \] This simplifies to: \[ \frac{(n_1 - 2)}{(n_1 - 1)} = \frac{2}{3} \] 5. **Cross-Multiplying**: Cross-multiply to solve for \( n_1 \): \[ 3(n_1 - 2) = 2(n_1 - 1) \] Expanding both sides: \[ 3n_1 - 6 = 2n_1 - 2 \] Rearranging gives: \[ 3n_1 - 2n_1 = 4 \implies n_1 = 4 \] 6. **Finding \( n_2 \)**: Now substitute \( n_1 \) back to find \( n_2 \): \[ n_2 = 2n_1 = 2 \times 4 = 8 \] ### Final Answer: The number of sides of the two polygons are \( n_1 = 4 \) and \( n_2 = 8 \).
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